document.write( "Question 1197973: A small company involved in e-commerce is interested in statistics concerning the use of e-mail. A poll found that 39% of a random sample of 1076 adults, who use a computer at their home, work, or school, said they do not send or receive e-mail. Complete parts a through e.
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document.write( " Find the margin of error for this poll if we want 95% confidence in our estimate of the percent of American adults who do not use e-mail.
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document.write( "Find that margin of error in 99% confidence
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Algebra.Com's Answer #831463 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "At 95% confidence, the z critical value is roughly z = 1.96 \n" ); document.write( "Use a table like this \n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf \n" ); document.write( "to get that value. Look at the bottom row labeled \"Z\" and above the 95% confidence level.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "phat = sample proportion \n" ); document.write( "phat = 0.39 \n" ); document.write( "n = sample size \n" ); document.write( "n = 1076\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "E = margin of error for a proportion \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n) \n" ); document.write( "E = 1.96*sqrt(0.39*(1-0.39)/1076) \n" ); document.write( "E = 0.02914386568497 \n" ); document.write( "E = 0.029 \n" ); document.write( "The margin of error is roughly 0.029 for the 95% confidence interval estimating the population proportion (p).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the 99% confidence interval, we'll repeat the same outline of steps. \n" ); document.write( "However, this time we'll use z = 2.576 which is found in the table linked above. \n" ); document.write( "The other values remain the same. \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n) \n" ); document.write( "E = 2.576*sqrt(0.39*(1-0.39)/1076) \n" ); document.write( "E = 0.0383033663288 \n" ); document.write( "E = 0.038\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answers: \n" ); document.write( "Margin of error at 95% confidence = 0.029 \n" ); document.write( "Margin of error at 99% confidence = 0.038 \n" ); document.write( "Round the values however instructed. \n" ); document.write( " \n" ); document.write( " |