document.write( "Question 1197943: The distribution of study times for first year students follows a Normal distribution with standard deviation = 55 minutes. Suppose a sample of 341 students found that the mean study time for these students was
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document.write( "= 189 minutes per week. Use this to find a 95% confidence interval to estimate the mean study time for all students.\r
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document.write( "We are 95% confident that the mean study time for first year students is between\r
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document.write( " ______ minutes and _______ minutes. \n" );
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Algebra.Com's Answer #831417 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Previously addressed: \n" ); document.write( " \n" ); document.write( " 95% confidence interval: z = 1.96 \n" ); document.write( " \n" ); document.write( " 189 ± 5.84 \n" ); document.write( "We are 95% confident that the mean study time for first year students is between \n" ); document.write( "183.16 minutes and 194.84 minutes. \n" ); document.write( "Round as directed \n" ); document.write( " \n" ); document.write( " |