document.write( "Question 1197869: There is a 8% chance of a certain type of light bulb being defective and there are 500 of these bulbs randomly sampled. Use the normal approximation to the binomial to find the following probabilities rounded to 3 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "a. Find the probability that fewer than 50 of the bulbs are defective.\r
\n" ); document.write( "\n" ); document.write( "b. Find the probability that more than 50 of the bulbs are defective.\r
\n" ); document.write( "\n" ); document.write( "c. Find the probability that between 40 and 50, inclusive, of the bulbs are defective.
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Algebra.Com's Answer #831314 by ewatrrr(24785)\"\" \"About 
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Binomial Distribution:
\n" ); document.write( "n = 500 , p = .08
\n" ); document.write( "Using the normal approximation and the NOted continuity correction factor.
\n" ); document.write( "(the continuity correction factor used as a Binomial Distribution is not continuous)
\n" ); document.write( " mean =500*.08= 40
\n" ); document.write( " sd = \"sqrt%28500%2A.08%2A.92%29\" = 6.07
\n" ); document.write( "Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus
\n" ); document.write( "P(x < 50 ) =P(x < 49.5 ), normpdf(-9999 49.5, 40, 6.07)= .941
\n" ); document.write( "P(x > 50) = P( x > 50.5) = normpdf(50.5,9999, 40, 6.07) = .042
\n" ); document.write( "P( 40 ≤ x ≤ 50) = = normcdf( 39.5,50.5, 40, 6.07) = .491
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