document.write( "Question 1197871: 750 eggs are randomly sampled from a population where 14% of all eggs are fertilized. Use the normal approximation to the binomial to find the following probabilities rounded to 3 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "a. Find the probability that exactly 106 of the eggs are fertilized. Correct\r
\n" ); document.write( "\n" ); document.write( "b. Find the probability that at least 106 of the eggs are fertilized. Incorrect\r
\n" ); document.write( "\n" ); document.write( "c. Find the probability that fewer than 106 of the eggs are fertilized. Incorrect\r
\n" ); document.write( "\n" ); document.write( "d. Find the probability that between 104 and 106, inclusive, of the eggs are fertilized.
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Algebra.Com's Answer #831312 by ewatrrr(24785)\"\" \"About 
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Binomial Distribution:
\n" ); document.write( "n = 750, p = .14
\n" ); document.write( "Using the normal approximation and the NOted continuity correction factor.
\n" ); document.write( "(the continuity correction factor used as a Binomial Distribution is not continuous)
\n" ); document.write( " mean = 750*.14 = 105
\n" ); document.write( " sd = \"sqrt%28750%2A.14%2A.86%29\" = 9.50
\n" ); document.write( "Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus
\n" ); document.write( "P(x = 106) = normcdf( 105.5,106.5, 105,9.5) = .0417
\n" ); document.write( "P(x ≥ 106) = normcdf( 105.5, 9999, 105, 9.5)= .4790
\n" ); document.write( "P(x < 106) = normcdf(-9999, 105.5, 105, 9.5)= .5210
\n" ); document.write( "P( 104 ≤ x ≤ 106) = = normcdf( 103.5,106.5, 105,9.5) = .1255
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