document.write( "Question 1197871: 750 eggs are randomly sampled from a population where 14% of all eggs are fertilized. Use the normal approximation to the binomial to find the following probabilities rounded to 3 decimal places.\r
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document.write( "a. Find the probability that exactly 106 of the eggs are fertilized. Correct\r
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document.write( "b. Find the probability that at least 106 of the eggs are fertilized. Incorrect\r
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document.write( "c. Find the probability that fewer than 106 of the eggs are fertilized. Incorrect\r
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document.write( "d. Find the probability that between 104 and 106, inclusive, of the eggs are fertilized. \n" );
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Algebra.Com's Answer #831312 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Binomial Distribution: \n" ); document.write( "n = 750, p = .14 \n" ); document.write( "Using the normal approximation and the NOted continuity correction factor. \n" ); document.write( "(the continuity correction factor used as a Binomial Distribution is not continuous) \n" ); document.write( " mean = 750*.14 = 105 \n" ); document.write( " sd = \n" ); document.write( "Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus \n" ); document.write( "P(x = 106) = normcdf( 105.5,106.5, 105,9.5) = .0417 \n" ); document.write( "P(x ≥ 106) = normcdf( 105.5, 9999, 105, 9.5)= .4790 \n" ); document.write( "P(x < 106) = normcdf(-9999, 105.5, 105, 9.5)= .5210 \n" ); document.write( "P( 104 ≤ x ≤ 106) = = normcdf( 103.5,106.5, 105,9.5) = .1255 \n" ); document.write( " |