document.write( "Question 1197863: A shipment of 10 printers contains 4 that are defective. Find the probability that a sample of size 4 , drawn from the 10 , will not contain a defective printer.
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Algebra.Com's Answer #831296 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "10 total, 4 defective \n" ); document.write( "10-4 = 6 not defective\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = 6/10 = probability first selection is not defective \n" ); document.write( "B = 5/9 = probability 2nd selection is not defective, given event A occurred prior (no replacement) \n" ); document.write( "C = 4/8 = probability 3rd selection is not defective, given events A & B occurred prior (no replacement) \n" ); document.write( "D = 3/7 = probability 4th selection is not defective, given events A,B,C occurred prior (no replacement)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "E = probability selecting four non-defective units \n" ); document.write( "E = A*B*C*D \n" ); document.write( "E = (6/10)*(5/9)*(4/8)*(3/7) \n" ); document.write( "E = (6*5*4*3)/(10*9*8*7) \n" ); document.write( "E = (2*3*5*2*2*3)/(2*5*3*3*2*2*2*7) \n" ); document.write( "E = (1)/(2*7) \n" ); document.write( "E = 1/14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 1/14 \n" ); document.write( " \n" ); document.write( " |