document.write( "Question 1197850: Crew A can assemble 2 cars in 5 days, and crew B can assemble 3 cars in 7 days. If both crews
\n" ); document.write( "together assemble 100 cars, with crew B working 10 days longer than crew A, how many days
\n" ); document.write( "(rounded to the nearest day) must each crew work?
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Algebra.Com's Answer #831290 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "CREW        RATE         \r\n" );
document.write( "A           2/5           \r\n" );
document.write( "B           3/7           \r\n" );
document.write( "A and B    29/35   \r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Combined Rate A and B
\n" ); document.write( "\"2%2F5%2B3%2F7\"\r
\n" ); document.write( "\n" ); document.write( "\"14%2F35%2B15%2F35\"\r
\n" ); document.write( "\n" ); document.write( "\"29%2F35\"\r
\n" ); document.write( "\n" ); document.write( "B worked 10 hours longer than both crews combined.
\n" ); document.write( "The two crews made 100 cars.\r
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\n" ); document.write( "\n" ); document.write( "Time for B alone to finish, x+10
\n" ); document.write( "Time A and B together, x\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28%2829%2F35%29x%2B%283%2F7%29%2A10=100%29\"---- B worked 10 hours beyond A.
\n" ); document.write( "unfinished --
\n" ); document.write( "x=115.5 days
\n" ); document.write( "seems strange
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