document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1197847>Question 1197847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this problem? 38+53=40+51=91<BR>\n" );
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document.write( "                                  2 51 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #831283 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13367)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=831283\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "I'm not sure what you are asking here....<br><BR>\n" );
document.write( "What you show is one way of thinking when you are asked to add 53 to 38.<br><BR>\n" );
document.write( "The thinking is that 38 is 2 short of 40, so you take 2 of the 53 and add it to the 38, making 40, and leaving 53-2 = 51 left to add.  Then 40 plus 51 is easy because there is no \"carry\".<br><BR>\n" );
document.write( "In mathematical notation, the process can be displayed like this:<br><BR>\n" );
document.write( "38 + 53 = 38 + (2 + 51) = (38 + 2) + 51 = 40 + 51 = 91<br><BR>\n" );
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