document.write( "Question 1197822: Let f(x)=[-x-3 , cubic root of x, x^2-x, x < -1, -1 < or equal x < 2, x > or equal 2
\n" ); document.write( "Find f(-1), f(1), and f(2)
\n" ); document.write( "

Algebra.Com's Answer #831248 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Some of what you typed in is a bit garbled. But I'm assuming this is what the piecewise function should look like
\n" ); document.write( "
\n" ); document.write( "If my assumption is incorrect, then please let me know.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "That piecewise function breaks down into 3 cases.
\n" ); document.write( "Case A: If \"x+%3C+-1\" then \"f%28x%29+=+-x-3\"
\n" ); document.write( "OR
\n" ); document.write( "Case B: If \"-1%3C=x+%3C+2\" then \"f%28x%29+=+root%283%2Cx%29\"
\n" ); document.write( "OR
\n" ); document.write( "Case C: If \"x%3E=2\" then \"f%28x%29+=+x%5E2-x\"
\n" ); document.write( "We can only pick exactly one case. This is because each interval mentioned has no overlap with any other.
\n" ); document.write( "There's no way, for instance, to have x be something smaller than -1 and larger than 2 at the same time.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To compute f(-1) we plug in x = -1
\n" ); document.write( "The input x = -1 fits the description of case B since -1 is in the interval \"-1%3C=x%3C2\"
\n" ); document.write( "I.e. \"-1+%3C=+-1%3C2\" is a true statement.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We'll plug x = -1 into the second piece.
\n" ); document.write( "\"f%28x%29+=+root%283%2Cx%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28-1%29+=+root%283%2C-1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28-1%29+=+root%283%2C%28-1%29%5E3%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28-1%29+=+-1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-----------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's compute f(1).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The input x = 1 fits the interval \"-1%3C=x%3C2\" so we'll go for case B again.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+root%283%2Cx%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%281%29+=+root%283%2C1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%281%29+=+root%283%2C1%5E3%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%281%29+=+1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-----------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Lastly let's find f(2).
\n" ); document.write( "The input x = 2 fits the interval \"x+%3E=+2\".
\n" ); document.write( "We'll go for case C this time.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+x%5E2-x\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%282%29+=+2%5E2-2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%282%29+=+2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-----------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Summary:
\n" ); document.write( "f(-1) = -1
\n" ); document.write( "f(1) = 1
\n" ); document.write( "f(2) = 2
\n" ); document.write( "
\n" ); document.write( "
\n" );