document.write( "Question 1197807: A metallurgist has one alloy containing 43% aluminum and another containing 63% aluminum. How many pounds of each alloy must he use to make 43 pounds of a third alloy containing 49% aluminum? \n" ); document.write( "
Algebra.Com's Answer #831232 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
A type of mixture problem asked very frequently. There are millions of these answered.\r
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\n" ); document.write( "\n" ); document.write( "43% and 63%;
\n" ); document.write( "want mixture 43 pounds of 49%;\r
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\n" ); document.write( "\n" ); document.write( "L=43
\n" ); document.write( "H=63
\n" ); document.write( "T=49
\n" ); document.write( "M=43, pounds of the mixture
\n" ); document.write( "y, unknown pounds of the H% alloy (63% alloy)\r
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\n" ); document.write( "\n" ); document.write( "\"Hy%2BL%28M-y%29=TM\"
\n" ); document.write( "-
\n" ); document.write( "\"Hy%2BLM-Ly=TM\"
\n" ); document.write( "\"%28H-L%29y=TM-LM\"
\n" ); document.write( "\"highlight%28y=M%28%28T-L%29%2F%28H-L%29%29%29\"
\n" ); document.write( "and you can find \"M-y\".\r
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\n" ); document.write( "\n" ); document.write( "Substitute your given values.\r
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\n" ); document.write( "\n" ); document.write( "--\r
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\n" ); document.write( "\n" ); document.write( "How much pounds the 63%:
\n" ); document.write( "\"43%28%2849-43%29%2F%2863-43%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"43%286%2F20%29\"\r
\n" ); document.write( "\n" ); document.write( "\"43%283%2F10%29\"\r
\n" ); document.write( "\n" ); document.write( "\"12.9\"------pounds of the 63% Al alloy
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