document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1197785>Question 1197785</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the line through the point  (3 , 5) that is perpendicular to the line 2X+5Y=4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #831216 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=831216\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "For solving using elementary methods, you can use the method shown by the other tutor: determine the slope of the graph of the given equation, find the slope of a line perpendicular to the given line, and use that slope and the given point to find the equation.<br><BR>\n" );
document.write( "You can solve the problem with much less work using this fact:<BR>\n" );
document.write( "Given a line with equation in the form Ax+By=C, the equation of any line PARALLEL to the given line is also of the form Ax+By=D, and the equation of any line PERPENDICULAR to the given line has an equation of the form Bx-Ay=E.<br><BR>\n" );
document.write( "So any line perpendicular to the given line 2x+5y=4 has an equation of the form 5x-2y=C.<br><BR>\n" );
document.write( "To find the one that passes through (3,5), substitute those values in the equation to determine the constant C:<br><BR>\n" );
document.write( "5(3)-2(5) = 15-10 = 5<br><BR>\n" );
document.write( "ANSWER: 5x-2y = 5<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );