document.write( "Question 1197776: Rounded to 2 decimal places, solve for k (the z-score) such that\r
\n" ); document.write( "\n" ); document.write( "P(−k < z < k) = 0.17\r
\n" ); document.write( "\n" ); document.write( "k=
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Algebra.Com's Answer #831173 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer: k = 0.21\r
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\n" ); document.write( "\n" ); document.write( "Explanation:\r
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\n" ); document.write( "\n" ); document.write( "There are many free online Z score calculators to use.
\n" ); document.write( "I recommend this one as it offers a diagram
\n" ); document.write( "https://davidmlane.com/normal.html
\n" ); document.write( "Click on the radio button \"Value from an area\"
\n" ); document.write( "Then type 0.17 into the \"area\" box. Leave the mean and SD as 0 and 1 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Then click on the \"between\" radio button to have \"-0.214 and 0.214\" show up.
\n" ); document.write( "You might have to click \"recalculate\".\r
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\n" ); document.write( "\n" ); document.write( "This tells us that P(-0.214 < z < 0.214) = 0.17 approximately\r
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\n" ); document.write( "\n" ); document.write( "When rounding to two decimal places, we write
\n" ); document.write( "P(-0.21 < z < 0.21) = 0.17
\n" ); document.write( "which shows k = 0.21\r
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