document.write( "Question 114191: Write the equivalent rate.\r
\n" ); document.write( "\n" ); document.write( "8. 72 ft/4 sec = ? yd/ 1 sec\r
\n" ); document.write( "\n" ); document.write( "Any help with this equation would be Greatly appreciated.
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Algebra.Com's Answer #83110 by MathLover1(20855)\"\" \"About 
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Write the equivalent rate. \r
\n" ); document.write( "\n" ); document.write( "8. \"72+ft%2F4+sec+=+x+yd%2F+1+sec\"\r
\n" ); document.write( "\n" ); document.write( "\"72+ft%2F4+sec\"…first see how many \"ft%2F1sec\", divide by \"4\"\r
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\n" ); document.write( "\n" ); document.write( "\"+%2872+ft%2F4+sec%29%2F4+=+%2872+ft%2F4%29%2F%284sec%2F4%29+=+%2818+ft%2F1sec%29+\"…… now \r
\n" ); document.write( "\n" ); document.write( "Since \"1+ft+=+0.33333+yd\" then \"+18+ft=+6+yd\",which means \"x=6\"
\n" ); document.write( "So we will have\r
\n" ); document.write( "\n" ); document.write( "\"72+ft%2F4+sec+=+6+yd%2F+1+sec\"
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