document.write( "Question 1197704: Sean deposited $1500 in bank,earning an interest of 3% per year.If he took out 1/3 of the money after 2 years and that the instrest was fixed at 3% each year,how many would he have left in the bank?
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Algebra.Com's Answer #831093 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "I'm assuming the interest is compounded annually.\r
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\n" ); document.write( "\n" ); document.write( "P = 1500 = deposit amount
\n" ); document.write( "r = 0.03 = decimal form of the 3% annual interest
\n" ); document.write( "n = 1 = compounding once per year
\n" ); document.write( "t = 2 = number of years\r
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\n" ); document.write( "\n" ); document.write( "A = P*(1+r/n)^(n*t)
\n" ); document.write( "A = 1500*(1+0.03/1)^(1*2)
\n" ); document.write( "A = 1500*(1+0.03)^(2)
\n" ); document.write( "A = 1500*(1.03)^(2)
\n" ); document.write( "A = 1500*1.0609
\n" ); document.write( "A = 1591.35\r
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\n" ); document.write( "\n" ); document.write( "Sean will have $1591.35 in the bank after 2 years.
\n" ); document.write( "1/3 of that amount is (1/3)*1591.35 = 530.45 which is the amount he withdraws.
\n" ); document.write( "There will be 1591.35 - 530.45 = 1060.90 dollars left in the bank.\r
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\n" ); document.write( "\n" ); document.write( "Alternative calculation:
\n" ); document.write( "(2/3)*1591.35 = 1060.90 dollars
\n" ); document.write( "This is because if he takes out 1/3 of the money, then 1-(1/3) = 2/3 of it remains.
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