document.write( "Question 1197670: The average student-loan debt is reported to be $25,235. A student believes that the student-loan debt is higher in her area. She takes a random sample of 100 college students in her area and determines the mean student-loan debt is $27,524 and the standard deviation is $6,000. Is there sufficient evidence to support the student's claim at a 5% significance level?
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document.write( "Is it safe to assume that n≤5%
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document.write( "of all college students in the local area?
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document.write( "No
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document.write( "Yes
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document.write( "Is n≥30?
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document.write( "Test the claim:\r
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document.write( "Determine the null and alternative hypotheses. Enter correct symbol and value.
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document.write( "H0: μ=
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document.write( "Determine the test statistic. Round to two decimals.
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document.write( "Find the
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document.write( "p
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document.write( " -value. Round to 4 decimals.
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Algebra.Com's Answer #831084 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Ho: µ = $25,235 \n" ); document.write( "Ha: µ > $25,235 \n" ); document.write( "n = 100, x̄ = $27,524 s = $6000 \n" ); document.write( " n = 100 , n≥ 30, standard Z distribution will be used.\r \n" ); document.write( "\n" ); document.write( "0.05 significance level, Critical value(df=99) = 1.6604 0r 1.645 standard \n" ); document.write( " \n" ); document.write( " 3.8167 > 1.645 Reject Ho \n" ); document.write( "P(z ≤ t-value) = .0001 < .05 Reject Ho \n" ); document.write( " |