document.write( "Question 1197674: Statistics students believe that the mean score on a first statistics test is 65. The instructor thinks that the mean score is higher. She samples 10 statistics students and obtains the scores:\r
\n" );
document.write( "\n" );
document.write( "Grades 65 64.3 88 69 83.2 68.4 96 64.3 65 62.7\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "Test grades are believed to be normally distributed.\r
\n" );
document.write( "\n" );
document.write( "Use a significance level of 5%.
\n" );
document.write( "State the mean of the sample:
\n" );
document.write( "85.08
\n" );
document.write( "Incorrect
\n" );
document.write( "State the standard error of the sample means:
\n" );
document.write( "State the test statistic:
\n" );
document.write( "t
\n" );
document.write( "=
\n" );
document.write( "
\n" );
document.write( "5.935830
\n" );
document.write( "Incorrect
\n" );
document.write( "State the p-value:
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #831046 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( "Mean = 72.59 \n" ); document.write( "Standard Error = 3.769746 \n" ); document.write( "Test Statistic = 2.01 \n" ); document.write( "P-value = 0.0377 \n" ); document.write( "Conclusion = \"Reject the null\" \n" ); document.write( "Interpretation = \"The mean score is higher than 65\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "With exception of the mean, each decimal value is approximate. \n" ); document.write( "Round however your teacher instructs.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "===============================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Null Hypothesis: mu = 65 \n" ); document.write( "Alternative Hypothesis: mu > 65 \n" ); document.write( "The inequality sign in the alternative hypothesis tells us we have a right-tailed test.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The data set is \n" ); document.write( "{65,64.3,88,69,83.2,68.4,96,64.3,65,62.7} \n" ); document.write( "There are n = 10 items in this data set.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add up all of the values in the data set to get \n" ); document.write( "65+64.3+88+69+83.2+68.4+96+64.3+65+62.7 = 725.9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide that sum by n = 10 to compute the mean \n" ); document.write( "mean = (sum of values)/n \n" ); document.write( "mean = (725.9)/10 \n" ); document.write( "mean = 72.59 \n" ); document.write( "This value is exact without any rounding done to it. \n" ); document.write( "This is the sample mean denoted as xbar. Its job is to estimate the population mean mu.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use a graphing calculator, spreadsheet, or statistical software to compute the standard deviation of the data set. \n" ); document.write( "We want the sample standard deviation. \n" ); document.write( "You should find the sample standard deviation is approximately s = 11.920985\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's compute the standard error (SE) \n" ); document.write( "SE = s/sqrt(n) \n" ); document.write( "SE = 11.920985/sqrt(10) \n" ); document.write( "SE = 3.76974645527023 \n" ); document.write( "SE = 3.769746 \n" ); document.write( "Round this however your teacher instructs.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we can find the test statistic \n" ); document.write( "t = (xbar - mu)/SE \n" ); document.write( "t = (72.59 - 65)/3.769746 \n" ); document.write( "t = 2.01339825017389 \n" ); document.write( "t = 2.01 \n" ); document.write( "Many stats textbooks I've come across will have the t statistic accurate to two decimal places. \n" ); document.write( "But if your teacher requires some other level of precision, then be sure to follow those instructions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sample size is n = 10 \n" ); document.write( "The degrees of freedom (df) is \n" ); document.write( "df = n-1 \n" ); document.write( "df = 10-1 \n" ); document.write( "df = 9 \n" ); document.write( "Use a stats calculator, spreadsheet, or similar to find the p-value is roughly 0.0377 \n" ); document.write( "This tells the reader that P(T > 2.01) = 0.0377 approximately when df = 9. \n" ); document.write( "The p-value may slightly vary depending if you use t = 2.01 or if you use more decimal digits in that test statistic such as t = 2.01339825017389 \n" ); document.write( "Either way, the p-value shouldn't differ too much.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The p-value being smaller than alpha = 0.05 tells us to reject the null and conclude that mu > 65 appears to be the case. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: we're doing a right tailed test, so be sure to find the area under the T distribution curve to the right of t = 2.01 \n" ); document.write( " \n" ); document.write( " |