document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1197676>Question 1197676</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4. There are 3 green cards, 4 red cards and 5 brown cards in a bag. What is the probability\r<BR>\n" );
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document.write( "a.) of getting a red card or a brown card after a green one (w/o replacement)?\r<BR>\n" );
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document.write( "b.) that a brown card is drawn first but not replaced, and a red card follows at the second draw?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #831045 by </B><A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><B>math_tutor2020(3817)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=831045\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "Part (a)\r<BR>\n" );
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document.write( "3 green + 4 red + 5 brown = 12 total<BR>\n" );
document.write( "3/12 = 1/4 represents the probability of getting a green card.\r<BR>\n" );
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document.write( "Since the card is not put back, there are 12-1 = 11 cards left.\r<BR>\n" );
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document.write( "4 red + 5 brown = 9 cards we want out of 11 left over.<BR>\n" );
document.write( "9/11 represents the probability of getting either red or brown on the second selection\r<BR>\n" );
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document.write( "(1/4)*(9/11) = 9/44 is the probability of getting green first, then red or brown second, where no replacement is made.\r<BR>\n" );
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document.write( "Answer: <font color=red>9/44</font>\r<BR>\n" );
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document.write( "Part (b)\r<BR>\n" );
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document.write( "5 brown out of 12 total<BR>\n" );
document.write( "5/12 =  probability of getting a brown card\r<BR>\n" );
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document.write( "12-1 = 11 cards left<BR>\n" );
document.write( "There are 4 red out of 11 left over<BR>\n" );
document.write( "4/11 =  probability of getting a red card after the first card is not replaced\r<BR>\n" );
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document.write( "(5/12)*(4/11) = (5*4)/(12*11)<BR>\n" );
document.write( "(5/12)*(4/11) = (5*4)/(4*3*11)<BR>\n" );
document.write( "(5/12)*(4/11) = 5/(3*11)<BR>\n" );
document.write( "(5/12)*(4/11) = 5/33<BR>\n" );
document.write( "This is the probability of getting brown first, then red next, assuming no replacements are made.\r<BR>\n" );
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document.write( "Answer: <font color=red>5/33</font><BR>\n" );
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