document.write( "Question 1197655: Find the coordinates of the focus for the parabola y=x^2 + 5x -2 \n" ); document.write( "
Algebra.Com's Answer #831023 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi  \r\n" );
document.write( "the vertex form of a Parabola opening up(a>0) or down(a<0), \r\n" );
document.write( "\"y=a%28x-h%29%5E2+%2Bk\" \r\n" );
document.write( "where(h,k) is the vertex  and  x = h  is the Line of Symmetry , \r\n" );
document.write( "the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)\r\n" );
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document.write( "y=x^2 + 5x -2\r\n" );
document.write( "y = (x -(5/2)^2 - 25/4 - 2 = (x -(5/2))^2  -33/4  \Vertex form\r\n" );
document.write( "V(-5/2, -33/4) p = 1/4  |the focus is (h,k + p)\r\n" );
document.write( "F(-5/2, -32/4)\r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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