document.write( "Question 1197446: hello please help me to solve this,thankyou!!
\n" ); document.write( "two hoses, when connected to a swimming pool, can fill the pool in 4 hours. If the larger hose alone is used, it can fill the pool in 6 hours less than the smaller hose how long will it take the smaller hose to fill the swimming pool alone? \n" ); document.write( "
Algebra.Com's Answer #830965 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "hello please help me to solve this,thankyou!!
\n" ); document.write( "two hoses, when connected to a swimming pool, can fill the pool in 4 hours. If the larger hose alone is used, it can fill the pool in 6 hours less than the smaller hose how long will it take the smaller hose to fill the swimming pool alone?
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Let time the smaller hose takes be S\r\n" );
document.write( "Then time the larger hose takes = S - 6\r\n" );
document.write( "Since both, when turned on, fills it in 4 hours, we get: \"matrix%281%2C3%2C+1%2FS+%2B+1%2F%28S+-+6%29%2C+%22=%22%2C+1%2F4%29\"\r\n" );
document.write( "                                                     4(S - 6) + 4S = S(S - 6) ------ Multiplying by LCD, 4S(S - 6)\r\n" );
document.write( "                                                        \r\n" );
document.write( "                                                                 0 = (S - 12)(S - 2)\r\n" );
document.write( "                 \r\n" );
document.write( "                 Time the smaller hose takes, working alone, or \"highlight_green%28matrix%281%2C4%2C+S%2C+%22=%22%2C+12%2C+hours%29%29\"       or        S = 2 hours (ignore)
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