document.write( "Question 1197439: There is a gambling game where equal-weight balls with numbers ranging from 1 to 15 are placed inside a tambiolo and mixed. Without replacement, three balls are chosen at random and are then chosen one by one.\r
\n" ); document.write( "\n" ); document.write( "(a) A certain casino customer named Mr. Han only has enough cash to place a total of 5 bets that evening. Mr. Han consistently bets that the 3 balls will be chosen, and that the greatest number will be at least as large as \"12\" among them. How likely is it that this will  happen?\r
\n" ); document.write( "\n" ); document.write( "(b) What is the likelihood that Mr. Han will finally strike it lucky and win on the 5th bet after a run of bad luck?
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Algebra.Com's Answer #830959 by Edwin McCravy(20054)\"\" \"About 
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Mr. Han will lose if the 3 balls are all chosen from balls 1 through 11.
\n" ); document.write( "That's 11C3 = 165 ways.\r
\n" ); document.write( "\n" ); document.write( "There are 15C3 = 455 ways the 3 balls can be selected, so there are 455-165=290
\n" ); document.write( "ways he can win.\r
\n" ); document.write( "\n" ); document.write( "So the probability that he wins a bet is \"290%2F455\" = \"58%2F91\".
\n" ); document.write( "That's the answer to (a)\r
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\n" ); document.write( "The probability that he loses a bet is \"1+-+58%2F91+=+33%2F91\". So the probability that he loses the first 4 and wins on the 5th is \r
\n" ); document.write( "\n" ); document.write( "\"%2833%2F91%29%5E4%2858%2F91%29\" which is about 0.011\r
\n" ); document.write( "\n" ); document.write( "Edwin\r
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