document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1197607>Question 1197607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joseph traveled from Boston to Framingham at 50 mph and then back to Boston at 40 mph. what was Joseph's average speed on the round trip<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #830941 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13209)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=830941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The other responses you have received use the same basic algebraic approach.<br><BR>\n" );
document.write( "Here is an alternative method that I personally find easier.<br><BR>\n" );
document.write( "The ratio of speeds is 50:40 = 5:4.  Since the distances there and back are the same, the ratio of times spent at the two speeds is 4:5.<br><BR>\n" );
document.write( "So 4/9 of the time was spent at 50mph and 5/9 of the time was spent at 40mph.  The average speed is then<br><BR>\n" );
document.write( "(4/9)50 + (5/9)40 = 200/9 + 200/9 = 400/9 = 44 4/9 mph<br><BR>\n" );
document.write( "ANSWER: 44 4/9 miles per hour<br><BR>\n" );
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