document.write( "Question 1197602: Water is pouring into an inverted cone at the rate of 8 cubic feet per minute. If the height of the cone is 12 ft and the radius of its base is 6 ft, how fast is the water level rising when the water is 4 ft deep? \n" ); document.write( "
Algebra.Com's Answer #830937 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The volume is increasing at a rate of 8 cubic feet per minute; we want to know how fast the water level (height) is changing when the height is 8 feet. \n" ); document.write( "Since we are given the rate of change of the volume and we want to find the rate of change of the height, we need a formula for the volume in terms of the height. \n" ); document.write( "Volume of a cone: \n" ); document.write( "The height of the cone is 12 feet and the radius of its base is 6 feet. Since the sides of the cone are straight, the ratio 6/12 = 1/2 of radius to height is constant. We want our formula in terms of height, so \n" ); document.write( " \n" ); document.write( "And the volume of the cone in terms of the height is \n" ); document.write( " \n" ); document.write( "Now we are ready to use our calculus for this related rates problem. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "We want the rate of change of the height, \n" ); document.write( " \n" ); document.write( "ANSWER: The water level is rising at a rate of (2/pi) feet per second when the water is 4 feet deep. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |