document.write( "Question 1197602: Water is pouring into an inverted cone at the rate of 8 cubic feet per minute. If the height of the cone is 12 ft and the radius of its base is 6 ft, how fast is the water level rising when the water is 4 ft deep? \n" ); document.write( "
Algebra.Com's Answer #830937 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The volume is increasing at a rate of 8 cubic feet per minute; we want to know how fast the water level (height) is changing when the height is 8 feet.

\n" ); document.write( "Since we are given the rate of change of the volume and we want to find the rate of change of the height, we need a formula for the volume in terms of the height.

\n" ); document.write( "Volume of a cone: \"%281%2F3%29%28base%29%28height%29=%281%2F3%29%28pi%2Ar%5E2%29%28h%29\"

\n" ); document.write( "The height of the cone is 12 feet and the radius of its base is 6 feet. Since the sides of the cone are straight, the ratio 6/12 = 1/2 of radius to height is constant. We want our formula in terms of height, so

\n" ); document.write( "\"r=%281%2F2%29h\"

\n" ); document.write( "And the volume of the cone in terms of the height is

\n" ); document.write( "\"V=%281%2F3%29%28pi%2A%28h%2F2%29%5E2%29%28h%29=%28pi%2F12%29h%5E3\"

\n" ); document.write( "Now we are ready to use our calculus for this related rates problem.

\n" ); document.write( "\"dV%2Fdt=%28pi%2F12%29%283h%5E2%29%28dh%2Fdt%29\"

\n" ); document.write( "\"dV%2Fdt=%28pi%2F4%29%28h%5E2%29%28dh%2Fdt%29\"

\n" ); document.write( "\"dh%2Fdt=%284%2F%28%28h%5E2%29pi%29%29%28dV%2Fdt%29\"

\n" ); document.write( "We want the rate of change of the height, \"dh%2Fdt\", when the height \"h\" is 4, knowing that the rate of change in the volume, \"dV%2Fdt\", is 8:

\n" ); document.write( "\"dh%2Fdt=%284%2F%28%28%284%29%5E2%29pi%29%29%288%29=32%2F%2816pi%29=2%2Fpi\"

\n" ); document.write( "ANSWER: The water level is rising at a rate of (2/pi) feet per second when the water is 4 feet deep.
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