document.write( "Question 1197533: Assume that a sample is used to estimate a population mean
\n" ); document.write( "μ Find the 99.5% confidence interval for a sample of size 331 with a mean of 65.6 and a standard deviation of 15.4. Enter your answer as a tri-linear inequality accurate to 3 decimal places. \n" ); document.write( "

Algebra.Com's Answer #830928 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Hi  \r\n" );
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document.write( "'Standard Distribution': µ = 65.5 and σ = 15.4\r\n" );
document.write( "n = 331\r\n" );
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document.write( " 99.5% confidence interval:  z = 2.807  |  Invnorm(.995 + .005/2) = Invnorm(.9975) \r\n" );
document.write( "   = 2.376\r\n" );
document.write( "65.5 - 2.376  < 65.5 + 2.376\r\n" );
document.write( "63.124 <  < 67.876\r\n" );
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document.write( "99.5% confident,  interval will contain true population mean\r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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