document.write( "Question 1197541: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval for a sample of size 146 with 63 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #830923 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "Hi \r\n" );
document.write( "  p(succes) = 63/146 = .4315  , p (failure) = .5685\r\n" );
document.write( "95% CI   ⇒   z = 1.96   |  2-sided  Invnorm( .95 + .05/2) = Invnorm(.975)\r\n" );
document.write( "ME = \"z%2Asqrt%28%28p%281-p%29%29%2Fn%29\"\r\n" );
document.write( "Plug and Play\r\n" );
document.write( "ME = \"1.96%2A%28sqrt%28%28.4315%29%28.5685%29%29%2F146%29%29\" = .0808\r\n" );
document.write( " .4315  ±  .0808\r\n" );
document.write( " CI(.351, .512)\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
document.write( "
\n" ); document.write( "
\n" );