document.write( "Question 1197545: Dupe's present age is 12 years older than seun's present age. Ten years ago, Dupe was three times seun's age. Find the present age of dupe and seun\r
\n" ); document.write( "\n" ); document.write( "I tried solving by saying (y+10)+(3y+10) = x + 12+x
\n" ); document.write( "I dont know whether it's correct, I would really appreciate if you help me solve it so i can study your solution because i have test tomorrow. THANK YOU SO MUCH
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Algebra.Com's Answer #830845 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "x = Seun's present age
\n" ); document.write( "x+12 = Dupe's present age\r
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\n" ); document.write( "\n" ); document.write( "Rewind the clock 10 years into the past
\n" ); document.write( "x-10 = Seun's age ten years ago
\n" ); document.write( "(x+12)-10 = x+2 = Dupe's age ten years ago\r
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\n" ); document.write( "\n" ); document.write( "We're told that at this point in time \"Dupe was three times Seun's age\".\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "Dupe's past age ten years ago = 3*(Seun's past age ten years ago)
\n" ); document.write( "x+2 = 3*(x-10)
\n" ); document.write( "x+2 = 3x-30
\n" ); document.write( "x-3x = -30-2
\n" ); document.write( "-2x = -32
\n" ); document.write( "x = -32/(-2)
\n" ); document.write( "x = 16
\n" ); document.write( "Seun's present age is 16 years.\r
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\n" ); document.write( "\n" ); document.write( "x+12 = 16+12 = 28 is Dupe's present age\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "Rewind the clock 10 years to find that Seun was 16-10 = 6 years old and Dupe was 28-10 = 18 years old.
\n" ); document.write( "Then notice the jump from 6 to 18 is \"times 3\", ie 6*3 = 18, to help confirm we have the correct ages.\r
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\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "Seun's present age = 16 years old
\n" ); document.write( "Dupe's present age = 28 years old
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