document.write( "Question 1197545: Dupe's present age is 12 years older than seun's present age. Ten years ago, Dupe was three times seun's age. Find the present age of dupe and seun\r
\n" ); document.write( "\n" ); document.write( "I tried solving by saying (y+10)+(3y+10) = x + 12+x
\n" ); document.write( "I dont know whether it's correct, I would really appreciate if you help me solve it so i can study your solution because i have test tomorrow. THANK YOU SO MUCH
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Algebra.Com's Answer #830836 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "let Dupe's present age be \"x\" and Seun's present age \"y\"\r
\n" ); document.write( "\n" ); document.write( "if Dupe's present age is \"12\" years older than seun's present age, we have\r
\n" ); document.write( "\n" ); document.write( "\"x=y%2B12\"......eq.1\r
\n" ); document.write( "\n" ); document.write( "if ten years ago, Dupe was three times seun's age, we have\r
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\n" ); document.write( "\n" ); document.write( "\"x-10=3%28y-10%29\".......eq.2, substitute \"x\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"y%2B12-10=3%28y-10%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y%2B2=3y-30\"\r
\n" ); document.write( "\n" ); document.write( "\"30%2B2=3y-y\"\r
\n" ); document.write( "\n" ); document.write( "\"32=2y\"\r
\n" ); document.write( "\n" ); document.write( "\"y=16\"\r
\n" ); document.write( "\n" ); document.write( "go to\r
\n" ); document.write( "\n" ); document.write( "\"x=y%2B12\"......eq.1, substitute \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=16%2B12\"\r
\n" ); document.write( "\n" ); document.write( "\"x=28\"\r
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\n" ); document.write( "\n" ); document.write( "so, the present age of Dupe is \"28\" and Seun is \"16\"\r
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