document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114159>Question 114159</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need Help, Please! \r<BR>\n" );
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document.write( "Use the product,quotient, and power rules of logarithms to rewrite the expression as a single logarithm. Assume that all variables represent positive real numbers.\r<BR>\n" );
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document.write( "1/2 log(2,x^4) + 1/4 log(2,x^4) - 1/6 log(2,x)\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83079 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83079\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2 log(2,x^4) + 1/4 log(2,x^4) - 1/6 log(2,x) <BR>\n" );
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document.write( "Keep in mind that all these logs are base 2:<BR>\n" );
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document.write( "log(x^4)^(1/2) + log(x^4)^(1/4) - log(x)^(1/6)\r<BR>\n" );
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document.write( "= log x^2 + log x - log x^(1/6)\r<BR>\n" );
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document.write( "= log[x^2*x/x^(1/6)]\r<BR>\n" );
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document.write( "= log[x^3/x^(1/6)]\r<BR>\n" );
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document.write( "= log[x^(17/6)]\r<BR>\n" );
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document.write( "= (17/6)log x<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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