document.write( "Question 1197478: A projectile is fired from a cliff 200 feet above the water at an inclination of 45° to the horizontal, with a muzzle velocity of 340 feet per second. The height h of the projectile above the water is given by ((-32x^2/(340^2) + x+200 where x is the horizontal distance of the projectile from the base of the cliff. Find the maximum height of the projectile. \n" ); document.write( "

Algebra.Com's Answer #830771 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Hi \r\n" );
document.write( "f(x) =  \r\n" );
document.write( "Using FREE padowan graphing software downloaded from www.padowan.dk\r\n" );
document.write( "the maximum height of the projectile =  ~ 1100Ft\r\n" );
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document.write( "setting the Derivative to zero to find maximum height:\r\n" );
document.write( "f'(x) =  -4x/7225 + 1  = 0  ⇒  x = 1806.25 \r\n" );
document.write( "f(1806.25) = 1103.125ft \r\n" );
document.write( " .\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
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