document.write( "Question 1197464: We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 68 had kids. Based on this, construct a 90% confidence interval for the proportion p of adult residents who are parents in this county.\r
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\n" ); document.write( " Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.\r
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Algebra.Com's Answer #830751 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Hi  \r\n" );
document.write( " n = 200,  p = 68/200 = .34  and q = .66 \r\n" );
document.write( "90% confidence interval ⇒  z = 1.96  2-sided Invnorm(.95) = 1.645\r\n" );
document.write( "ME = = .055\r\n" );
document.write( ".34 - .055 < p < .34 + .055\r\n" );
document.write( ".285 < p < .395\r\n" );
document.write( " 0r\r\n" );
document.write( "p = .34 ± .055\r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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