document.write( "Question 1197460: You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately
\n" ); document.write( "σ= 33.8 You would like to be 98% confident that your estimate is within 10 of the true population mean. How large of a sample size is required?
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Algebra.Com's Answer #830737 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi  \r\n" );
document.write( " 98% confident ⇒  z = 2.326\r\n" );
document.write( "σ = 33.8,   ME = 10\r\n" );
document.write( "How large of a sample size is required?\r\n" );
document.write( "\"ME+=+z%2Asigma%2Fsqrt%28n%29\"\r\n" );
document.write( "0r\r\n" );
document.write( "n = \"%28+z%2Asigma%2FME%29%5E2\"\r\n" );
document.write( "n = \"%28%282.326%2A33.8%29%2F10%29%5E2+%29%29\" = 61.8  0r sample Size = 62 (always round Up)\r\n" );
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document.write( " = CI	z = value\r\n" );
document.write( "90%	z =1.645\r\n" );
document.write( "92%	z = 1.751\r\n" );
document.write( "95%	z = 1.96\r\n" );
document.write( "98%	z = 2.326  Invnorm(.99)  2-sided (.98 + .02/2 = .99 )\r\n" );
document.write( "99%	z = 2.576\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
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