document.write( "Question 1197406: SETTING UP AND SOLVING DIRECT AND INVERSE PROPORTIONS
\n" );
document.write( "Two sump pumps working at the same rate to drain a flooded basement in 5 1/2 hours. How long would it have taken 3 pumps working at the same rate to drain the basement? I think it is an inverse proportion and I put 2 over 3 = 5 1/2 over x multiplied and got 2x=16 1/2 divided and got 8 1/4. But it is supposed to take less time not more. \n" );
document.write( "
Algebra.Com's Answer #830663 by josgarithmetic(39625)![]() ![]() ![]() You can put this solution on YOUR website! Are these identical sump pumps? \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This example seems to be a Constant Rates type problem, easier to handle like that.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x, the time needed for 1 pump to do the job.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The question, how much time for three pumps together to do the job? \n" ); document.write( "One pump alone needs 11 hours; but for three pumps to do 1 job, \n" ); document.write( "t hours \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 hours 40 minutes \n" ); document.write( " |