document.write( "Question 1197406: SETTING UP AND SOLVING DIRECT AND INVERSE PROPORTIONS
\n" ); document.write( "Two sump pumps working at the same rate to drain a flooded basement in 5 1/2 hours. How long would it have taken 3 pumps working at the same rate to drain the basement? I think it is an inverse proportion and I put 2 over 3 = 5 1/2 over x multiplied and got 2x=16 1/2 divided and got 8 1/4. But it is supposed to take less time not more.
\n" ); document.write( "

Algebra.Com's Answer #830663 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
Are these identical sump pumps? \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This example seems to be a Constant Rates type problem, easier to handle like that.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x, the time needed for 1 pump to do the job.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1%2Fx%2B1%2Fx=1%2F%285%261%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"2%2Fx=1%2F%2811%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2Fx=2%2F11\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28x=11%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The question, how much time for three pumps together to do the job?
\n" ); document.write( "One pump alone needs 11 hours; but for three pumps to do 1 job,
\n" ); document.write( "t hours
\n" ); document.write( "\"%283%2F11%29t=1\"\r
\n" ); document.write( "\n" ); document.write( "\"t=11%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28t=3%262%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "3 hours 40 minutes
\n" ); document.write( "
\n" );