document.write( "Question 114024: Please help me with the following. Thank you very much.
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Algebra.Com's Answer #83066 by Edwin McCravy(20056)\"\" \"About 
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Please help. Thank you very much
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document.write( "When 24x-3 is non-negative, the following are true\r\n" );
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document.write( "1.   f(x) = |24x-3| = +(24x-3) = 24x-3\r\n" );
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document.write( "2.    24x-3 > 0\r\n" );
document.write( "        24x > 3\r\n" );
document.write( "          x > \"3%2F24\"\r\n" );
document.write( "          x > \"1%2F8\" \r\n" );
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document.write( "Therefore f(x) = 24x-3 when x > \"1%2F8\"\r\n" );
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document.write( "When 24x-3 is negative, the following are true\r\n" );
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document.write( "1.   f(x) = |24x-3| = -(24x-3) = -24x+3\r\n" );
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document.write( "2.    24x-3 < 0\r\n" );
document.write( "        24x < 3\r\n" );
document.write( "          x < \"3%2F24\"\r\n" );
document.write( "          x < \"1%2F8\" \r\n" );
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document.write( "Therefore f(x) = -24x+3 when x < \"1%2F8\"\r\n" );
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document.write( "Now we put those together:\r\n" );
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document.write( "f(x) =  24x-3 when x > \"1%2F8\"\r\n" );
document.write( "f(x) = -24x+3 when x < \"1%2F8\"\r\n" );
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document.write( "We normally write this as:\r\n" );
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document.write( "       ì 24x-3 when x > 1/8\r\n" );
document.write( "f(x) = í\r\n" );
document.write( "       î-24x+3 when x < 1/8\r\n" );
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document.write( "The graph of f(x) looks like this:\r\n" );
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document.write( "\"graph%28200%2C50%2C-1.3%2C1.3%2C-1.3%2C1.3%2Cabs%2824x-3%29%29\"\r\n" );
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document.write( "Edwin
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