document.write( "Question 1197391: The line width of a tool used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer.
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document.write( "(a) What is the probability that a line width is greater than
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document.write( "0.62 micrometer?
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document.write( "(b) What is the probability that a line width is between 0.47 and 0.63 micrometer?
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document.write( "(c) The line width of 90% of samples is below what value? \n" );
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Algebra.Com's Answer #830646 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Hi \r\n" ); document.write( "\r\n" ); document.write( "Normal Distribution: µ = .5 and σ = .05\r\n" ); document.write( "Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus\r\n" ); document.write( "normalcdf(smaller value, larger value, µ, σ).\r\n" ); document.write( "\r\n" ); document.write( "P(x >.62 ) = normalcdf( .62, 9999, .5, .05) = .0082\r\n" ); document.write( "P(.47 ≤ x ≤ .63) = normalcdf( .47, .63, .5, .05) = .7211\r\n" ); document.write( "\r\n" ); document.write( "The line width of 90% of samples is below what value\r\n" ); document.write( " z= Invnorm(.90) = 1.28\r\n" ); document.write( "\n" ); document.write( " |