document.write( "Question 1197396: A rectangular piece of metal is 15 in longer than it is wide. Squares with sides 3 in long are cut from the four corners and the flaps are folded upward to form an open box. If the volume of the box is 1092 in^3, what were the original dimensions of the piece of metal?
\n" );
document.write( "What is the original width? \n" );
document.write( "
Algebra.Com's Answer #830643 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! x, the width of the rectangle piece \n" ); document.write( "x+15, length of the rectangle piece \n" ); document.write( "3, HEIGHT of the box formed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The base area becomes \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "VOLUME is \n" ); document.write( "\n" ); document.write( "This may be solvable through checking factoring.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "- \n" ); document.write( " |