document.write( "Question 1197341: You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable preliminary estimation for the population proportion. You would like to be 90% confident that you estimate is within 2.5% of the true population proportion. How large of a sample size is required? \n" ); document.write( "
Algebra.Com's Answer #830572 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "Hi  \r\n" );
document.write( " 90% confident ⇒  z = 1.645, \r\n" );
document.write( "p = .50(Generally .5 is used if p is not given)  ME = .025\r\n" );
document.write( "How large of a sample size is required?\r\n" );
document.write( "n = \"%28z%2FME%29%5E2+%28p%281-p%29%29%29\"\r\n" );
document.write( "n = \"%281.645%2F.025%29%5E2+%28.5%28.5%29%29%29\" = 1082.41  0r sample Size = 1083 (always round Up)\r\n" );
document.write( "\r\n" );
document.write( " = CI	z = value\r\n" );
document.write( "90%	z =1.645\r\n" );
document.write( "92%	z = 1.751\r\n" );
document.write( "95%	z = 1.96\r\n" );
document.write( "98%	z = 2.326\r\n" );
document.write( "99%	z = 2.576\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
document.write( "

\n" ); document.write( " \n" ); document.write( "
\n" );