document.write( "Question 114052: how would i solve these using factoring :D .\r
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document.write( "1- (x - 2)(2x - 5) = 0\r
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document.write( "2- x^2 + 6x - 27 = 0\r
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document.write( "3- x^2 + 6 = -5x
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Algebra.Com's Answer #83054 by edjones(8007)![]() ![]() You can put this solution on YOUR website! (x - 2)(2x - 5) = 0 \n" ); document.write( "It is already factored. \n" ); document.write( "x-2=0 \n" ); document.write( "x=2, \n" ); document.write( "2x-5=0 \n" ); document.write( "2x=5 \n" ); document.write( "x=5/2 \n" ); document.write( ". \n" ); document.write( "x^2 + 6x - 27 = 0 \n" ); document.write( "we know the signs will be different because the last sign is minus. \n" ); document.write( "we know the larger number will be + because the sign in front of 6 is +. \n" ); document.write( "What 2 different signed factors of 27 add up to +6? 9 and -3. \n" ); document.write( "(x+9)(x-3)=0 \n" ); document.write( "x=-9, x=3 \n" ); document.write( ". \n" ); document.write( "x^2 + 6 = -5x \n" ); document.write( "We have to rearrange the equation. \n" ); document.write( "x^2+5x+6=0 \n" ); document.write( "we know the signs will be the same because the last sign is +. \n" ); document.write( "we know they will be + because the middle sign is +. \n" ); document.write( "what 2 factors of six add up to 5? 3 and 2. \n" ); document.write( "(x+3)(x+2)=0 \n" ); document.write( "x=-3, x=-2 \n" ); document.write( ". \n" ); document.write( "Ed\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |