document.write( "Question 1197301: Write the 4 terms of the Geometric Sequence: If the sum of the first and fourth terms is 195, and the sum of the second and the third term is 60 \n" ); document.write( "
Algebra.Com's Answer #830526 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Let's use the standard notation of a for the first term and r for the common ratio. Then

\n" ); document.write( "The sum of the first and fourth terms is 195:
\n" ); document.write( "\"a%2Bar%5E3=195\"
\n" ); document.write( "\"a%281%2Br%5E3%29=195\" [1]

\n" ); document.write( "The sum of the second and third terms is 60:
\n" ); document.write( "\"ar%2Bar%5E2=60\"
\n" ); document.write( "\"a%28r%29%281%2Br%29=60\" [2]

\n" ); document.write( "It should be clear that both a and r are integers, since both sums are integers.

\n" ); document.write( "So a quick informal method of solving the problem is to look at equation [1] and find what integer r can be so that (1+r^3) is a factor of 195.

\n" ); document.write( "r=1 --> 1+r^3=2 --> not a factor of 195
\n" ); document.write( "r=2 --> 1+r^3=9 --> not a factor of 195
\n" ); document.write( "r=3 --> 1+r^3=28 --> not a factor of 195
\n" ); document.write( "r=4 --> 1+r^3=65 --> YES -- 195 = 3(65)

\n" ); document.write( "So it looks as if a=3 and r=4 are the values we are looking for. Let's check that.

\n" ); document.write( "The sequence is 3, 12, 48, 192. 3+192 = 195, and 12+48 = 60.

\n" ); document.write( "ANSWER: The geometric sequence is 3, 12, 48, and 192.

\n" ); document.write( "Note that the sequence could also be 192, 48, 12, 3 -- with first term 192 and common ratio 1/4.

\n" ); document.write( "For a formal (and ugly) algebraic solution, using equations [1] and [2] above....

\n" ); document.write( "\"%28a%281%2Br%5E3%29%29%2F%28a%28r%29%281%2Br%29%29=195%2F60=13%2F4\"
\n" ); document.write( "\"%28a%281%2Br%29%281-r%2Br%5E2%29%29%2F%28a%28r%29%281%2Br%29%29=195%2F60\"
\n" ); document.write( "\"%281-r%2Br%5E2%29%2Fr=13%2F4\"
\n" ); document.write( "\"4%281-r%2Br%5E2%29=13r\"
\n" ); document.write( "\"4-4r%2B4r%5E2=13r\"
\n" ); document.write( "\"4r%5E2-17r%2B4=0\"
\n" ); document.write( "\"%284r-1%29%28r-4%29=0\"

\n" ); document.write( "This gives us the two values we found above for the common ratio: r=4 or r=1/4.

\n" ); document.write( "And that leads us quickly to the two sequences we found.

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