document.write( "Question 1197272: The scores on an exam follow a normal distribution with mean 79 and standard deviation 6.5. What is the approximate probability that a randomly selected exam taker had a score below 85.5? Give your answer as a decimal with two digits after the decimal.
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Algebra.Com's Answer #830486 by Theo(13342)\"\" \"About 
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mean is 79.
\n" ); document.write( "standard deviation is 6.5
\n" ); document.write( "z = (x-m)/s
\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the raw score
\n" ); document.write( "m is the mean
\n" ); document.write( "s is the standard deviation.
\n" ); document.write( "for this problem:
\n" ); document.write( "z = (85.5 - 79) / 6.5 = 1
\n" ); document.write( "probability of getting a z-score below 1 = area to the left of the z-score = .8413447404 = .84 rounded to 2 decimal places.
\n" ); document.write( "that's the same as probability of getting a raw score below 85.5.
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