document.write( "Question 1197256: Find the 10th term of the sequence -37,-34,-41 \n" ); document.write( "
Algebra.Com's Answer #830471 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "As the response from tutor @ikleyn says, the problem is nonsense; there is no way to know what the subsequent terms of the sequence are. ANY following numbers make a valid sequence. \n" ); document.write( "Tutor @MathLover1 assumes the sequence is quadratic and obtains a solution. It is true that, given a sequence of 3 terms, there is a unique polynomial function of degree 2 for which f(1), f(2), and f(3) are the three given numbers. \n" ); document.write( "But the problem does not say that the sequence is quadratic; it is bad mathematics to assume it is. Furthermore, there are an infinite number of polynomials of degree greater than 2 which produce the given first three numbers. \n" ); document.write( "A third \"obvious\" pattern is that the sequence of differences \"plus 3, minus 7\" repeats, giving the sequence \n" ); document.write( "-37, -34, -41, -38, -45, -42, -49, -46, -53, -50 \n" ); document.write( "In that sequence, the \"obvious\" 10th term is -50. \n" ); document.write( "So go with the answer from tutor @ikleyn: The problem as posed is nonsense. \n" ); document.write( " \n" ); document.write( " |