document.write( "Question 1197252: find the are of a quadrilateral having points (5,2), (4,3), (2,4), (-8,-1) as consecutive vertices. \n" ); document.write( "
Algebra.Com's Answer #830462 by Alan3354(69443)\"\" \"About 
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find the are of a quadrilateral having points A(5,2), B(4,3), C(2,4), D(-8,-1) as consecutive vertices.
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document.write( " A   B   C   D   A\r\n" );
document.write( " 5   4   2  -8   5\r\n" );
document.write( " 2   3   4  -1   2\r\n" );
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\n" ); document.write( "Add the diagonal products starting at the upper left:
\n" ); document.write( "5*3 + 4*4 + 2*-1 + -8*2 = 15 + 16 - 2 - 16 = 13
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\n" ); document.write( "Add the diagonal products starting at the lower left:
\n" ); document.write( "2*4 + 3*2 + 4*-8 + -1*5 = 8 + 6 -32 - 5 = -23
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\n" ); document.write( "The difference between the sums is 36.
\n" ); document.write( "1/2 of 36 is the area
\n" ); document.write( "Area = 18 sq units\r
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