document.write( "Question 1197253: find the distance of the point (12,7)from the line through (5,3), (2,-3) \n" ); document.write( "
Algebra.Com's Answer #830447 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Let's find the slope of the line through (5,3) and (2,-3)
\n" ); document.write( "(x1,y1) = (5,3)
\n" ); document.write( "(x2,y2) = (2,-3)\r
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\n" ); document.write( "\n" ); document.write( "m = slope\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-3+-+3%29%2F%282+-+5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-6%29%2F%28-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+2\"\r
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\n" ); document.write( "\n" ); document.write( "Now apply point-slope form
\n" ); document.write( "y-y1 = m(x - x1)
\n" ); document.write( "y-3 = 2(x - 5)
\n" ); document.write( "y-3 = 2x - 10
\n" ); document.write( "y = 2x - 10+3
\n" ); document.write( "y = 2x - 7
\n" ); document.write( "This is in y = mx+b form\r
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\n" ); document.write( "\n" ); document.write( "Let's get everything to one side
\n" ); document.write( "y = 2x - 7
\n" ); document.write( "0 = 2x - 7 - y
\n" ); document.write( "0 = 2x - y - 7
\n" ); document.write( "2x-y-7 = 0
\n" ); document.write( "This is now in the form Ax+By+C=0 with A = 2, B = -1, C = -7\r
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\n" ); document.write( "\n" ); document.write( "Now we'll use the formula discussed here
\n" ); document.write( "https://en.wikipedia.org/wiki/Distance_from_a_point_to_a_line
\n" ); document.write( "I'll use slightly different notation
\n" ); document.write( "The A,B,C will be the same
\n" ); document.write( "Instead of (x0,y0) I'll refer to the point not on the line as (p,q)\r
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\n" ); document.write( "\n" ); document.write( "The distance from (p,q) to the line Ax+By+C = 0 is \"d+=+%28abs%28Ap%2BBq%2BC%29%29%2F%28sqrt%28A%5E2%2BB%5E2%29%29\" where point (p,q) is not on the line mentioned.\r
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\n" ); document.write( "\n" ); document.write( "We'll plug in A = 2, B = -1, C = -7
\n" ); document.write( "And also p = 12 and q = 7 from the point (12,7)
\n" ); document.write( "\"d+=+%28abs%28Ap%2BBq%2BC%29%29%2F%28sqrt%28A%5E2%2BB%5E2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+%28abs%282%2A12%2B%28-1%29%2A7%2B%28-7%29%29%29%2F%28sqrt%282%5E2%2B%28-1%29%5E2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+%28abs%2824-7-7%29%29%2F%28sqrt%285%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+%28abs%2810%29%29%2F%28sqrt%285%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+10%2F%28sqrt%285%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+%2810%2Asqrt%285%29%29%2F%28sqrt%285%29%2Asqrt%285%29%29\" Multiply top and bottom by sqrt(5) to rationalize the denominator\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+%2810%2Asqrt%285%29%29%2F%28%28sqrt%285%29%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+%2810%2Asqrt%285%29%29%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+2%2Asqrt%285%29\" is the exact distance from (12,7) to the line 2x-y-7 = 0 which goes through (5,3) and (2,-3)\r
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\n" ); document.write( "\n" ); document.write( "-------------------------------------------\r
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\n" ); document.write( "\n" ); document.write( "Verification:
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\n" ); document.write( "I used GeoGebra to make this image. \r
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\n" ); document.write( "\n" ); document.write( "The red line 2x-y-7 = 0 was what we found earlier through (5,3) and (2,-3)
\n" ); document.write( "The black line x+2y-26 = 0 is perpendicular to the red line, and it goes through point A(12,7)
\n" ); document.write( "Use whichever method you prefer to solve that system of 2 equations to find the red and black line intersect at D(8,9)
\n" ); document.write( "Then use the distance formula to find the distance from A(12,7) to D(8,9) is exactly \"2%2Asqrt%285%29\" units.\r
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\n" ); document.write( "\n" ); document.write( "Side note:
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