document.write( "Question 1197250: Suppose a die is rolled twice and let
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document.write( "A={first toss is a prime} B={second toss is even}
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document.write( "Find the requested probability.(enter the probability as a fraction)\r
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document.write( "P(A n B) \n" );
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Algebra.Com's Answer #830446 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A={first toss is a prime} \n" ); document.write( "B={second toss is even}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "set of prime numbers between 1 and 6 = {2, 3, 5} \n" ); document.write( "set of even numbers between 1 and 6 = {2, 4, 6}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(A) = probability that the first toss is a prime \n" ); document.write( "P(A) = (number of primes between 1 and 6)/(number of faces on the die) \n" ); document.write( "P(A) = 3/6 \n" ); document.write( "P(A) = 1/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(B) = (number of even numbers between 1 and 6)/(number of faces on the die) \n" ); document.write( "P(B) = 3/6 \n" ); document.write( "P(B) = 1/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(A n B) = probability both A and B occur \n" ); document.write( "P(A n B) = P(A)*P(B) which works since the events are independent \n" ); document.write( "P(A n B) = (1/2)*(1/2) \n" ); document.write( "P(A n B) = 1/4 \n" ); document.write( " \n" ); document.write( " |