document.write( "Question 1197236: Zhao wants $7,000 saved in 2 years to make a down payment on a house. How much money should she invest now at 6.1% compounded annually in order to meet her goal?
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Algebra.Com's Answer #830422 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "Answer: $6218.24\r
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\n" ); document.write( "\n" ); document.write( "Work Shown:
\n" ); document.write( "A = 7000 dollars is needed two years from now
\n" ); document.write( "P = unknown deposit amount
\n" ); document.write( "r = 0.061 = decimal form of the 6.1% interest rate
\n" ); document.write( "n = 1 = to represent compounding annually
\n" ); document.write( "t = 2 = number of years\r
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\n" ); document.write( "\n" ); document.write( "Solve for P using the compound interest formula
\n" ); document.write( "A = P*(1+r/n)^(n*t)
\n" ); document.write( "7000 = P*(1+0.061/1)^(1*2)
\n" ); document.write( "7000 = P*(1+0.061)^(2)
\n" ); document.write( "7000 = P*(1.061)^(2)
\n" ); document.write( "7000 = P*1.125721
\n" ); document.write( "7000 = 1.125721P
\n" ); document.write( "1.125721P = 7000
\n" ); document.write( "P = 7000/1.125721
\n" ); document.write( "P = 6218.23702320557 approximately
\n" ); document.write( "P = 6218.24\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "A = P*(1+r/n)^(n*t)
\n" ); document.write( "A = 6218.24*(1+0.061/1)^(1*2)
\n" ); document.write( "A = 7000.00335104
\n" ); document.write( "A = 7000.00
\n" ); document.write( "The answer is confirmed.
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