document.write( "Question 1197236: Zhao wants $7,000 saved in 2 years to make a down payment on a house. How much money should she invest now at 6.1% compounded annually in order to meet her goal?
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Algebra.Com's Answer #830422 by math_tutor2020(3816)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: $6218.24\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Work Shown: \n" ); document.write( "A = 7000 dollars is needed two years from now \n" ); document.write( "P = unknown deposit amount \n" ); document.write( "r = 0.061 = decimal form of the 6.1% interest rate \n" ); document.write( "n = 1 = to represent compounding annually \n" ); document.write( "t = 2 = number of years\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for P using the compound interest formula \n" ); document.write( "A = P*(1+r/n)^(n*t) \n" ); document.write( "7000 = P*(1+0.061/1)^(1*2) \n" ); document.write( "7000 = P*(1+0.061)^(2) \n" ); document.write( "7000 = P*(1.061)^(2) \n" ); document.write( "7000 = P*1.125721 \n" ); document.write( "7000 = 1.125721P \n" ); document.write( "1.125721P = 7000 \n" ); document.write( "P = 7000/1.125721 \n" ); document.write( "P = 6218.23702320557 approximately \n" ); document.write( "P = 6218.24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "A = P*(1+r/n)^(n*t) \n" ); document.write( "A = 6218.24*(1+0.061/1)^(1*2) \n" ); document.write( "A = 7000.00335104 \n" ); document.write( "A = 7000.00 \n" ); document.write( "The answer is confirmed. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |