document.write( "Question 1197232: If sec x= 3/2 and cosec y= 3; determine cos (x+y)\r
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Algebra.Com's Answer #830419 by Theo(13342)\"\" \"About 
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sec(x) = 3/2 becomes:
\n" ); document.write( "1/cos(x) = 3/2 which becomes:
\n" ); document.write( "cos(x) = 2/3.
\n" ); document.write( "when cos(x) = 2/3, solve for sin(x) to get sin(x) = sqrt(5)/3
\n" ); document.write( "confirm by cos^2(x) + sin^2(x) = 1 which becomes:
\n" ); document.write( "(2/3)^2 + (sqrt(5)/3)^2 = 1\r
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\n" ); document.write( "\n" ); document.write( "you have:
\n" ); document.write( "cos(x) = 2/3
\n" ); document.write( "sin(x) = sqrt(5)/3\r
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\n" ); document.write( "\n" ); document.write( "cosec(y) = 3 becomes:
\n" ); document.write( "1/sin(y) = 3 which becomes:
\n" ); document.write( "sin(y) = 1/3
\n" ); document.write( "when sin(y) = 1/3, solve for cos(y) to get cos(y) = sqrt(8)/3
\n" ); document.write( "confirm by cos^2(y) + sin^2(y) = 1 which becomes:
\n" ); document.write( "(sqrt(8)/3)^2 + (1/3)^2 = 1\r
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\n" ); document.write( "\n" ); document.write( "you have:
\n" ); document.write( "cos(y) = sqrt(8)/3
\n" ); document.write( "sin(y) = 1/3\r
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\n" ); document.write( "\n" ); document.write( "put theme together, you have:
\n" ); document.write( "cos(x) = 2/3
\n" ); document.write( "cos(y) = sqrt(8)/3
\n" ); document.write( "sin(x) = sqrt(5)/3
\n" ); document.write( "sin(y) = 1/3\r
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\n" ); document.write( "\n" ); document.write( "cos(x+y) = cos(x)cos(y)-sin(x)sin(y) which becomes
\n" ); document.write( "cos(x+y) = 2/3*sqrt(8)/3 - sqrt(5)/3*1/3 which is equal to .3800873636.\r
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\n" ); document.write( "\n" ); document.write( "i also used my calculator to confirm this is true.
\n" ); document.write( "sec(x) = 3/2 becomes 1/cos(x) = 3/2 which becomes cos(x) = 2/3
\n" ); document.write( "cosec(y) = 3 becomes 1/sin(y) = 3 which becomes sin(y) = 1/3
\n" ); document.write( "arccos(2/3) = 48.1896851 degrees.
\n" ); document.write( "arcsin(1/3) = 19.47122063 degrees.
\n" ); document.write( "48.1896851 + 19.47122063 = 67.66090574 degrees.
\n" ); document.write( "cos(67.66090574) = .3800873636.\r
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