document.write( "Question 1197232: If sec x= 3/2 and cosec y= 3; determine cos (x+y)\r
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Algebra.Com's Answer #830418 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! If sec x= 3/2 and cosec y= 3; determine cos (x+y) \n" ); document.write( "---------- \n" ); document.write( "sec = 3/2 ---> cos(x) = 2/3 \n" ); document.write( " \n" ); document.write( "---- \n" ); document.write( "csc = 3 ----> sin(y) = 1/3 \n" ); document.write( " \n" ); document.write( "========================== \n" ); document.write( "cos(x+y) = cos(x)*cos(y) - sin(x)*sin(y) ------ I'm pretty sure. \n" ); document.write( "Look it up at \"half-angle formulas\" on Wikipedia. \n" ); document.write( " \n" ); document.write( " |