document.write( "Question 1197227: The nut shack hazelnuts for 7.00 per pound and peanuts for 4.50 per pound how much of each type should be used to make a 24 pound mixture that sells for 5.54 per pound round answers to the nearest pounds
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\n" ); document.write( "Pounds of peanut nuts
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Algebra.Com's Answer #830405 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Let: \r
\n" ); document.write( "\n" ); document.write( "\"x\"=hazelnuts\r
\n" ); document.write( "\n" ); document.write( "\"y\"=peanuts\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "Therefore:\r
\n" ); document.write( "\n" ); document.write( " \"x+%2B+y+=+24\"...........eq.1\r
\n" ); document.write( "\n" ); document.write( " \"7.00x+%2B+4.50y+=+5.54+%2A24\"\r
\n" ); document.write( "\n" ); document.write( "\"7.00x+%2B+4.50y+=+132.96\".........eq.2\r
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\n" ); document.write( "\n" ); document.write( "By using the substitution method:\r
\n" ); document.write( "\n" ); document.write( " \"y+=+24+-+x\".............eq. 1a (from the first equation)\r
\n" ); document.write( "\n" ); document.write( "Substituting this value of \"x\" into the 2nd equation we can solve for \"y\":\r
\n" ); document.write( "\n" ); document.write( " \"7.00x+%2B+4.50%28+24+-+x%29+=+132.96+\"\r
\n" ); document.write( "\n" ); document.write( " \"7.00x+%2B+108+-+4.5x=+132.96+\"\r
\n" ); document.write( "\n" ); document.write( " \"2.5x+%2B+108=132.96+\"\r
\n" ); document.write( "\n" ); document.write( " \"2.5x+=132.96+-+108\"\r
\n" ); document.write( "\n" ); document.write( " \"x+=24.96%2F2.5\"\r
\n" ); document.write( "\n" ); document.write( " \"x+=9.984\".........round to the nearest pounds\r
\n" ); document.write( "\n" ); document.write( " \"x+=10\"\r
\n" ); document.write( "\n" ); document.write( "Putting this value of \"x\" into the eq.1a we can solve for \"y\":\r
\n" ); document.write( "\n" ); document.write( " \"y+=+24+-+10\".............eq. 1a \r
\n" ); document.write( "\n" ); document.write( " \"y+=+14+\"\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "Therefore the answer is:\r
\n" ); document.write( "\n" ); document.write( " \"10\" pounds of hazelnut \r
\n" ); document.write( "\n" ); document.write( "\"14\" pounds of peanuts
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