document.write( "Question 1197199: If Machine A makes a yo-yo every five minutes and Machine B takes ten minutes to make a yo-yo, how many hours would it take them working together to make 20yo−yos? \n" ); document.write( "

Algebra.Com's Answer #830361 by ikleyn(52803) $\"\"$ $\"About$

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\n" ); document.write( "If Machine A makes a yo-yo every five minutes and Machine B takes ten minutes to make a yo-yo,
\n" ); document.write( "how many hours would it take them working together to make 20 yo−yos?
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document.write( "We assume that both machines started simultaneously.\r\n" );
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document.write( "Every 10 minutes, machine A produces 2 yo-yo; every 10 minutes machine B produces 1 yo-yo.\r\n" );
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document.write( "So, two machines produce 3 yo-yo every 10 minutes.\r\n" );
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document.write( "Divide 20 by 3 with a remainder: 20/3 = 6 + 2/3.\r\n" );
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document.write( "It tells you that in 6*10 = 60 minutes two machines will produce 6*3 = 18 yo-yos,\r\n" );
document.write( "which is still less than 20 yo-yous.\r\n" );
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document.write( "In the next 5 minutes, machine A will produce the 19-th yo-yo.\r\n" );
document.write( "In the next 5 minutes, machine A will produce the 20-th yo-yo, and machine B will complete the 21-th yo-yo.\r\n" );
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document.write( "Thus 20 yo-yo (and even 21 (!) yo-yo) will be completed 70 minutes after start moment.\r\n" );
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document.write( "70 minutes is the minimal time to wait to have 20 yo-yos completed.\r\n" );
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