document.write( "Question 1197195: If Machine A can make a yo-yo every 5 minutes and Machine B can make a yo-yo every 10 minutes, how long wold it take them working together to make 20 yo-yo's? \n" ); document.write( "
Algebra.Com's Answer #830360 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "@josgarithmetic has the right idea, but you'll need to round up to the nearest multiple of 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The answer is 70 minutes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "70/5 = 14 yo-yo's are made by machine A \n" ); document.write( "70/10 = 7 yo-yo's are made by machine B \n" ); document.write( "That gives a total of 14+7 = 21 yo-yo's\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We won't be able to land on 20 exactly, but it's better to go over the goal than come up short.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At the 65 minute mark, \n" ); document.write( "65/5 = 13 yo-yo's are made by machine A \n" ); document.write( "65/10 = 6.5 = 6 yo-yo's are made by machine B \n" ); document.write( "giving a total of 13+6 = 19 yo-yo's \n" ); document.write( "An extra 1 minute and 40 seconds will not be enough time for either machine to produce that final yo-yo needed. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |