document.write( "Question 1197180: The highway fuel economy of a 2016 Lexus RX 350 FWD 6-cylinder 3.5-L automatic 5-speed using premium fuel is a normally distributed random variable with a mean of μ=22.25 mpg and a standard deviation of σ=1.50 mgp.\r
\n" ); document.write( "\n" ); document.write( "a) What is the standard error of X (with a line on top), the mean form a random sample of 36 fill-ups by one driver? (Round your answer to 4 decimal places.)\r
\n" ); document.write( "\n" ); document.write( "b) Within what interval would you expect the sample mean to fall, with 99 percent probability? (Round your answer to 4 decimal places.)
\n" ); document.write( "

Algebra.Com's Answer #830357 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "Hi  \r\n" );
document.write( "n = 36      µ = 22.25 and σ = 1.50  \r\n" );
document.write( "a) \"SE+=+sigma%2Fsqrt%28n%29\"\r\n" );
document.write( "SE = 1.50 / √36 =    1.5/6 = .25\r\n" );
document.write( "b) Within what interval would you expect the sample mean to fall, \r\n" );
document.write( "with 99 percent probability? \r\n" );
document.write( "\"ME+=+z%2Asigma%2Fsqrt%28n%29\"  Interval is  22.25 ± ME\r\n" );
document.write( "99% confience interval:  z = 2.576\r\n" );
document.write( " ME = 2.576(.25) = 1.394\r\n" );
document.write( "22.25 -1.394< \"mu\" < 22.25 + 1.394\r\n" );
document.write( " CI(20.856, 23.644)\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" );