document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1196991>Question 1196991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A right circular cylindrical tank of radius 3 m and altitude 12 m rests on its element. The tank is partially filled with fuel oil, the greatest depth of the oil being 1 m . If the tank were to be raised up and made to rest upon one of its circular bases, how deep would the tank then be? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #830332 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=830332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A right circular cylindrical tank of radius 3 m and altitude 12 m rests on its element. The tank is partially filled with fuel oil, the greatest depth of the oil being 1 m . If the tank were to be raised up and made to rest upon one of its circular bases, how deep would the tank then be?<BR>\n" );
document.write( "Why \"greatest depth?\"<BR>\n" );
document.write( "Assuming it's uniform depth, and \"on its element\" means its axis is parallel to the ground:<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Find the volume of the oil:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Vol%2F12+=+r%5E2%2Aarccos%28%28r-h%29%2Fr%29+-+%28r-h%29%2Asqrt%282rh+-+h%5E2%29 ALIGN=MIDDLE  ALT=\"Vol%2F12+=+r%5E2%2Aarccos%28%28r-h%29%2Fr%29+-+%28r-h%29%2Asqrt%282rh+-+h%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  --- From CRC tables<BR>\n" );
document.write( "Vol/12 = 3^2*arccos(2/3) - 2*sqrt(6 - 1)<BR>\n" );
document.write( "Vol/12 = 9*0.8410687 - 4.472136<BR>\n" );
document.write( "Vol = 37.169788 cubic meters<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "Vol standing on end = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2%2Ah ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+Vol%2F%28pi%2Ar%5E2%29 ALIGN=MIDDLE  ALT=\"h+=+Vol%2F%28pi%2Ar%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "1.3146 meters<BR>\n" );
document.write( " </SPAN>\n" );
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