document.write( "Question 1197173: When two balanced dice are rolled, 36 equally likely outcomes are possible. Let X denote the sum of the dice. a) What are the possible values of the random variable X ? b) Use random-variable notation to represent the event that the sum of the dice is 7. c) Find P(X = 7). d) Find the probability distribution of X . Leave your probabilities in fraction form. e) Construct a probability histogram for X. \n" ); document.write( "
Algebra.Com's Answer #830319 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Part (a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "X = sum of the two dice\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Assuming we have two standard six-sided dice, each labeled 1 through 6, then the possible values of X are: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 \n" ); document.write( "due to this sum of dice chart here \n" ); document.write( "
\n" ); document.write( "Eg: 1 + 6 = 7 in the top right corner.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------- \n" ); document.write( "Part (b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here are all the possible ways to get a sum of 7 \n" ); document.write( "1+6 = 7 \n" ); document.write( "2+5 = 7 \n" ); document.write( "3+4 = 7 \n" ); document.write( "4+3 = 7 \n" ); document.write( "5+2 = 7 \n" ); document.write( "6+1 = 7 \n" ); document.write( "I'm not exactly sure what your teacher is referring to when mentioning \"Use random-variable notation\". \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It's possible that your teacher wants you to write P(X = 7) for the answer here.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I recommend getting a second opinion from your teacher, another classmate, or another tutor.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------- \n" ); document.write( "Part (c)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In the previous part, there were 6 ways to get a sum of 7 \n" ); document.write( "This is out of 36 total outcomes \n" ); document.write( "6/36 = 1/6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(X = 7) = 1/6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------- \n" ); document.write( "Part (d)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We'll follow the same idea as part (c), but do so for X = 2 all the way up to X = 12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(X = 2) = 1/36 since there is one way to get a sum of 2 out of 36 total outcomes\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(X = 3) = 2/36 since there are two ways to get a sum of 3 out of 36 total outcomes\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(X = 4) = 3/36 since there are three ways to get a sum of 4 out of 36 total outcomes\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And so on until reaching P(X = 7) = 6/36 \n" ); document.write( "So far the numerators have increased: 1,2,3,4,5,6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then we have a countdown of numerators: 5,4,3,2,1 when going through P(X = 8) to P(X = 12)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's what the probability distribution looks like \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If your teacher requires you to reduce each fraction, then be sure to do so. \n" ); document.write( "Here is each reduction \n" ); document.write( "2/36 = 1/18 \n" ); document.write( "3/36 = 1/12 \n" ); document.write( "4/36 = 1/9 \n" ); document.write( "6/36 = 1/6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------- \n" ); document.write( "Part (e)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Refer to the table in part (d) \n" ); document.write( "Each P(X) value tells us how tall the bar will be for any particular X value. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Example: The first bar is 1/36 units tall since P(X) = 1/36 when X = 2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is what the histogram would look like \n" ); document.write( " ![]() \n" ); document.write( "This distribution is symmetric since the left half is a mirror copy of the right half. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |